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radius of an arc


Posted by JT on December 19th, 1997 06:26 PM
In reply to arcs by Keith on December 19th, 1997 12:26 PM [Go to top of thread]

Kieth, let me rephrase what I think you are asking
and you tell me if it's correct. The 36" dimension
represents a chord of a circle (i.e. a line connecting
two points on a circle) and the 6" dimension is the
distance from the chord to the edge of the circle
at the midpoint of the chord. If that is what you
want, the formula is: R = (1/2)x(((CxC)/(4xh))+h).
R = radius
C = chord length
h = arc height
x = multiplication, eg. c x c = c squared
/ = division
() = order of evaluation

So in your case:
R = (1/2)x(((36x36)/(4x6))+6)
= .5 x ((1296/24) + 6)
= .5 x (54 + 6) = .5 x 60 = 30".

Forumulas sure look ugly when you have to type them
out, but there it is.



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Topic History:

  • arcs by Keith  12/19/97 12:26 PM

Topic Follow-ups:

  • To JT by Keith Bowman  1/23/98 05:44 PM




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